Skip to main content

What is (100-100) / (100-100)?



What is (100-100) / (100-100)?

First, we should follow the order of operations (PEMDAS)
  1. Parentheses and groups
  2. Exponents and radicals
  3. Multiplication
  4. Division
  5. Addition
  6. Subtractions
We need to solve what is inside the parentheses first:
(100–100) (100–100)
(100–100) = 0
Now, we can substitute this 0 in for both (100–100)s.
0
This is a problem because you cannot divide something by 0. It just doesn’t work. You can’t do it.
You can’t split 1 cake into zero pieces: it’s either one piece, 2 half pieces, 3 third pieces. If it’s not there, it is zero whatever pieces. You can’t split the cake into pieces that don’t exist.
In math, we say that 0/0 is undefined.
Therefore, (100–100) / (100–100) = undefined

Comments

Popular posts from this blog

how is tan (A+B) = [tan A + tan B]/[1 - tan A tan B]?

How is tan (A+B) = [tan A + tan B]/ [1 - tan A tan B]? Method 1: Let A = 30 deg and B = 45 deg. LHS = tan (30+45) = tan 75 = 3.732050808 RHS = [tan A + tan B]/[1 - tan A tan B] = [tan 30 + tan 45]/[1 - tan 30 tan 45] = [0.577350269 + 1]/[1 - 0.577350269*1] = 1.577350269/0.42264973 = 3.732050808 = LHS Proved. Method 2: tan (A+B) = [tan A + tan B]/[1 - tan A tan B] RHS = [tan A + tan B]/[1 - tan A tan B] =[(sin A/cos A) + (sin B/cos B)]/[1-(sin A/cos A)(sin B/cos B) = [sin A cos B + cos A sin B]/[cos A cos B][1 - sin A sin B/(cos A cos B)] = sin (A+B)/{[cos A cos B][cos A cos B - sin A sin B]/(cos A cos B)} = sin (A+B)/[cos A cos B - sin A sin B = sin (A+B)/cos (A+B) = tan (A+B) = LHS. Proved. Thanks. source:Quara

What are the last 3 digit of 2^2017?

I will provide two methods for this. Method 1  (Easy way) : USE A CALCULATOR. You will get the answer in a matter of seconds like I got. Clearly, the answer is 072. Method 2  (Slight harder way) : Here, I want to find the answer without using the calculator. Let's try it. Note :- I will be making use of  Congruence Modulo  and  Euler's Theorem , so these are the prerequisites. Another way to put the question is  “Find the remainder when  2 2017 2 2017  is divided by 1000”. First of all we factorise 1000 as: 1000 = 2 3 × 5 3 1000 = 2 3 × 5 3 Next, we find the remainder by  2 3 2 3  and  5 3 5 3 seperately. It's obvious that  2 3 2 3  divides  2 2017 2 2017 . Hence, 2 2017 ≡ 0 ( m o d 8 ) 2 2017 ≡ 0 ( m o d 8 ) Now to find the remainder by 125 (or 5^3), we use Euler's Theorem. Euler's theorem is applicable in this case since  g c d ( 2 , 125 ) = 1 g c d ( 2 , 125 ) = 1 . Φ ( 125 ) = ...

What is the application of linear equations in two variables in daily life?

In life X = our happiness, life, dreams, desires etc Y = caring for others, other's happiness, value we give to others. In daily life X + Y = Compromise, sacrifice, adjustments but still maintaining happiness of X & Y factors. Stay happy stay blessed Thank you  They are used in solving linear inequalities, which are then used to solve linear programming problems. Now, linear programming, as widely known solves problems about many situations in daily life. It helps you know which food products to buy for requisite nutrition at the least cost, how to travel max. distance in least fuel, how to price your products for a max. profit, and many more